Quoteand 16-24 GB LPDDR5X VRAM.
If it's still 16 GB RAM / unified memory, that would be disappointing.
QuoteThis GPU could power one of the next-generation RDNA 5 desktop GPUs.
Sure, just like the RX 6700 non-XT powers the PS5 (=not a custom GPU die).
QuoteYes, laptop memory isn't typically used for desktop-class GPUs, but it is not impossible.
PS5 448.0 GB/s. Let's say PS6 will be 50% faster, so it needs 50% higher memory bandwidth: 448 GB/s * 1.5 = 672 GB/s (raw GPU performance is memory-bound, so this number must be achieved / is a must). What kind of a memory bit bus width interface would be needed for 672 GB/s? Using LPDDR5X-8000 memory, it would be: 672 GB/s =
672-bit*8000 MT/s / 1000 / 8.
For comparison:
- Strix Halo is using 256-bit and LPDDR5X-8000. 256-bit is the same as a quad-channel desktop (workstation) PC (a normal PC is dual-channel (2*64-bit per channel = 128-bit)).
- An Apple M5 Max is 614 GB/s (en.wikipedia.org/wiki/Apple_M5). And you know the prices of those M5 Max-based devices (it even rhymes, so it must be true..I mean high [prices]).
So is it possible? Yes, but the price would be ridiculous (in the vicinity of a M5 Max device). But since the 670 GB/s number is a must (RTX 5070 type of performance, btw.), how to achieve it otherwise, but not using such a wide and expensive memory interface? Easy, either use GDDR7 memory (PS5 uses GDDR6 (techpowerup.com/gpu-specs/playstation-5-gpu.c3480), so it would be a natural continuation) or the use of fast 16000 MT/s LPDDR6(X) memory (= 2x the bandwidth per bit), which would about halven the required memory bit bus interface to 336-bit (24-bit per LPDDR6(X) channel * 28 LPDDR6 chips): 672 GB/s = 336-bit * 16000 / 1000 / 8.
Gorgon Halo (256-bit memory interface) is up to 192 GB. This is 16 LPDDR5X chips at 16-bit per channel -> 192 GB / 16 chips = 12 GB per chip. But the PS6 is not 192 GB, it's 16 GB to 24 GB (according to this news's rumor), so how do you get that using LPDDR5X or LPDDR6(X)? 672-bit / 16-bit per chip = 42 chips (the answer to the you know what question). 42 * 0.5 GB per chip = 21 GB (V)RAM / unified memory. I guess it works out, but it would be 42 chips (plus/minus). 32 chips for 16 GB VRAM and 48 chips for 24 GB VRAM. Using a RTX 5070' GDDR7 and 672 GB/s as an example: 192-bit / 32-bit per GDDR7 chip = 6 chips, which is much more convenient.
GDDR7: 672 GB/s / 192-bit = 3.5 GB/s per bit.
LPDDR5X (using 8000 MT/s): 672 GB/s / 672-bit = 1 GB/s per bit.
LPDDR6(X) (using 16000 MT/s): 672 GB/s / 336-bit = 2 GB/s per bit.
The wider the memory bit bus width, the bigger and more expensive the GPU will be.
Even a 336-bit wide APU interface using LPDDR6(X) wouldn't be cheap (a 32 GB Strix Halo mini-PC is like $2000 and now multiply it by 1.3 (336/256)).
It's gonna be GDDR7(X), unless (the calculated) 0.5 GB per chip, low density LPDDR5X or LPDDR6(X) memory chips are so much cheaper that it works out, but the price per GB for both memory types is about the same for the usual densities and I don't think 0.5 GB densities will be that much cheaper.
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